A bowling ball is dropped from a height of 24 feet.

a. Write a function that gives the height h (in feet) of the bowling ball after t seconds. h (t) = ?

b. Find the height of the bowling ball after 1 second. The height of the ball after 1 second is feet.

c. How long does the bowling ball take to hit the ground? Round your answer to the nearest hundredth of a second. The bowling ball takes about __ seconds to hit the ground.

a. H = (1/2) * a*t^2

B. h=16.09ft

C. t = 1.22s

Explanation:

Explanation: Newton's equation of motion. This is called motion under free fall.

S=ut + (1/2) * a*t^2

Let S=H, and a=g

1.

H=ut + (1/2) * g*t^2

H=distance covered in ft (24ft)

u = initial velocity (ft/s)

t = time covered in seconds

g=acceleration due to gravity (ft/s^2)

a=g (32.185ft/s)

When u=0

H = (1/2) * g*t^2

2. H = (1/2) * g*t^2

g=32.185ft/s^2

t=1s

Juxtaposing the values into the equation

H = (1/2) * 32.185 * (1) ^2

H=16.09ft

3. When the maximum distance covered is 24ft, then using

H = (1/2) * a*t^2

24=0.5*32.165*t^2

24=16.09t^2

1.491=t^2

Find the square root of both sides

t=1.22s

It takes 1.22s to hit the ground