Ask Question
12 May, 06:43

Tired of being chased by a jaguar, you set a trap. Hoping to drop it on the jaguar, you try to push a

44.0 kg stone boulder off of the edge of a cliff that slopes down at an angle of 15.0°. Being weak with

hunger, the best you can do is push the boulder with a force of 222 N. The coefficient of kinetic friction

between the boulder and the ground is is 0.700. (Ignore static friction.)

What is the acceleration of the boulder while you push it down the incline?

+3
Answers (1)
  1. 12 May, 08:01
    0
    Answer: acceleration = 3.27m/s^2

    Explanation:

    Given that the

    Mass M = 44kg

    Angle Ø = 15 degree

    Coefficient of friction ų = 0.7

    Force F = 222N

    F - Fr = ma ... (1)

    Where Fr = frictional force

    Fr = ųN

    N = normal reaction = mg

    Fr = ųmgsinØ

    Fr = 0.7 * 44 * 9.81 * sin 15

    Fr = 78.2N

    Substitutes Fr, F and M into equation one.

    222 - 78.2 = 44a

    143.79 = 44a

    Make a the subject of formula

    a = 143.79/44

    Acceleration a = 3.27 m/s^2
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “Tired of being chased by a jaguar, you set a trap. Hoping to drop it on the jaguar, you try to push a 44.0 kg stone boulder off of the edge ...” in 📘 Physics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers