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19 November, 07:21

two blocks with masses 2 kg and 4 kg are pushed from rest by the same amount of fore for a distance of 100 m on a frictionless floor. the final kinetic energy of the 2 kg block after the 100 m distance is

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  1. 19 November, 08:08
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    the kinetic energy of the 2 kg mass after the 100 m is equal to 1962 J

    Explanation:

    mass of block A = 2 kg

    mass of block B = 4 kg

    distance the blocks were pushed = 100 m

    NB: Blocks were pushed the same distance at the same equal time period. And the ground is without friction.

    Work done in moving the 2 kg mass along the 100 m distance is,

    work = force x distance moved

    force exerted by the 2 kg mass = 2 x 9.81 m/s^2 (acceleration due to gravity)

    force = 19.62 N

    therefore,

    work done = 19.62 x 100 = 1962 Joules of work.

    According to energy conservation principles, the kinetic energy impacted of the 2 kg mass through this distance will be equal to the work done in moving the 2 kg mass through this distance.

    Therefore, the kinetic energy of the 2 kg mass after the 100 m is equal to 1962 J
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