During an all-night cram session, a student heats up a 0.607 liter (0.607 x 10 - 3 m3) glass (Pyrex) beaker of cold coffee. Initially, the temperature is 16.2 °C, and the beaker is filled to the brim. A short time later when the student returns, the temperature has risen to 93.5 °C. The coefficient of volume expansion of coffee is the same as that of water. How much coffee (in cubic meters) has spilled out of the beaker?

Question

Physics

Broderick

22 February, 14:43

During an all-night cram session, a student heats up a 0.607 liter (0.607 x 10 - 3 m3) glass (Pyrex) beaker of cold coffee. Initially, the temperature is 16.2 °C, and the beaker is filled to the brim. A short time later when the student returns, the temperature has risen to 93.5 °C. The coefficient of volume expansion of coffee is the same as that of water. How much coffee (in cubic meters) has spilled out of the beaker?

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Answers (1)

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Kailey Hancock · Answer 1

Answer: 0.00000938422m^3

Explanation:

dV=Vø*β * (t1-tø)

The parameters are

dV is the change in volume after temperature increase

Vø = 0.607 * 10^-3m3 is the initial vokume of coffe at 16.2^0 C

β = coefficient of volume expansion of water at 16.2^0 C is 0.0002/0C

t1 = 93.5^0C final temperature

tø=16.2^0 C

Therefore

dV=0.607 * 10^-3 * 0.0002 * (93.5-16.2)

dV = 0.00000938422m^3

This is the volume of coffee that will spill over the container