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16 July, 06:54

What average mechanical power (in W) must a 70.5 kg mountain climber generate to climb to the summit of a hill of height 365 m in 49.0 min? Note: Due to inefficiencies in converting chemical energy to mechanical energy, the amount calculated here is only a fraction of the power that must be produced by the climber's body. HINT

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  1. 16 July, 08:09
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    Work done by mountain climber against his weight

    = mgH

    = 70.5 X 9.8 X 365

    = 252178.5 J

    Power = work done / time taken to do work

    = 252178.5 / (49 x 60)

    = 85.775 J/s

    = 85.775 W.
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