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16 January, 16:54

A boat has a mass of 4040 kg. Its engines generate a drive force of 4660 N due west, while the wind exerts a force of 880 N due east and the water exerts a resistive force of 1400 N due east. Take west to be the positive direction. What is the boat's acceleration, with correct sign?

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Answers (2)
  1. 16 January, 19:13
    0
    Given:

    Mass of the boat, m = 4040 kg

    The driving force of engine, FB = 4660 N in west = + 4660 N

    The force of wind, Fwi = 880 N in east = - 880 N

    The force of water, Fwa = 1400 N in east = - 1400N

    Total three forces are acting on the boat

    Fnet = Fb+fwi+Fwa

    Fnet = 4660 - 880 - 1400

    Fnet = + 2380N

    Acceleration (a) = Force/mass

    = 2380/4040

    = 0.59m/s2
  2. 16 January, 20:35
    0
    Answer: acceleration = 0.59m/s2

    Direction is due west

    Explanation: M = 4040

    F1 = 4660

    F2=1400

    F3=880

    Net force = F1 - (F2 + F3)

    = 4660 - (1400 + 880)

    =2380

    Acceleration (a) = F/M

    = 2380/4040

    = 0.59m/s2
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