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4 September, 12:04

You catch a volleyball (mass 0.270 kg) that is moving downward at 7.50 m/s. In stopping the ball, your hands and the volleyball descend together a distance of 0.150 m. How much work do your hands do on the volleyball in the process of stopping it?

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  1. 4 September, 15:38
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    deceleration a

    v² = u² - 2as

    0 = 7.5² - 2 a x. 15

    a = 187.5 m / s²

    If R be the force exerted by hand

    R - mg = ma

    R = mg + ma

    =.27 (9.8 + 187.5)

    = 53.27 N

    Work done by hand

    = force x displacement

    = 53.27 x -.15

    = - 8 J
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