Ask Question
14 March, 04:50

10) A bowling ball released from rest at the top of a 200. m building falls to the ground under the influ-

ence of gravity. Calculate:

a) its speed at 5.00 s

b) how far it has gone when its speed is 32.0"

+3
Answers (1)
  1. 14 March, 05:26
    0
    Given:

    v₀ = 0 m/s

    a = 9.8 m/s²

    a) Find v when t = 5.00 s.

    v = at + v₀

    v = (9.8 m/s²) (5.00 s) + 0 m/s

    v = 49.0 m/s

    b) Find Δx when v = 32.0 m/s.

    v² = v₀² + 2aΔx

    (32.0 m/s) ² = (0 m/s) ² + 2 (9.8 m/s²) Δx

    Δx = 52.2 m
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “10) A bowling ball released from rest at the top of a 200. m building falls to the ground under the influ- ence of gravity. Calculate: a) ...” in 📘 Physics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers