Ask Question
16 March, 21:54

A crate with a mass of 186 kg sits flat on a horizontal surface. If the person slides the crate with constant velocity across the floor with a force of 273 N, what is the coefficient of kinetic friction between the crate and the floor?

+4
Answers (1)
  1. 16 March, 22:11
    0
    0.15

    Explanation:

    mass, m = 186 kg

    Force, F = 273 N

    Let μ be the coefficient of friction

    As the block is moving with constant velocity so acceleration is zero.

    Let f be the friction force.

    F - f = ma

    273 - f = 0

    f = 273

    μ mg = 273

    μ x 186 x 9.8 = 273

    μ = 0.15

    Thus, the coefficient of friction is 0.15.
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “A crate with a mass of 186 kg sits flat on a horizontal surface. If the person slides the crate with constant velocity across the floor ...” in 📘 Physics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers