Two positive charges of magnitude 20 micro C and 100 micro C are placed at a distance of 150cm. Calculate the electric force of repulsion between them.

Question

Physics

Hill

27 March, 12:14

Two positive charges of magnitude 20 micro C and 100 micro C are placed at a distance of 150cm. Calculate the electric force of repulsion between them.

+5

Answers (1)

Know the Answer?

Alyson · Answer 1

Answer:800N

Explanation:

Force of repulsion = kq1q2/r^2

Q1 = 20*10^-6

Q2=100*10^-6

R=150cm=0.15m

K = 9*10^9

F = 2*10^-5*1*10^-4*9*10^9 / (0.15) ^2

F = 2*1*9*10^-5-4+9 / (0.15) ^2

F = 18*10^0 / (0.15) ^2

F=18/0.0225

F=800N