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7 October, 08:07

A 45.0 g golf ball moves to the right 273 km/h and strikes another ball at rest. they collide elastically and the golf ball moves to the left 91 km/h. If the other ball moves 182 km/h to the right, what is its mass?

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Answers (2)
  1. 7 October, 10:07
    0
    The mass of the other ball = 90 g

    Explanation:

    From the law of conservation of momentum,

    Total momentum before collision = total momentum after collision

    m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂

    Where m₁ = mass of the golf ball, m₂ = mass of the other ball, u₁ = initial velocity of the gulf ball, u₂ = initial velocity of the other ball, v₁ = final velocity of the gulf ball, v₂ = final velocity of the other ball.

    Note: The other ball was at rest, therefore u₂ = 0 m/s

    m₁u₁ = m₁v₁ + m₂v₂

    making m₂ the subject of the equation above,

    m₂ = (m₁u₁-m₁v₁) / v₂ ... Equation 1

    Given: m₁ = 45 g, u₁ = 273 km/h, v₁ = - 91 km/h (moves to the left), v₂ = 182 km/h

    Substituting these values into equation 1

    m₂ = [45*273 - 45 (-91) ]/182

    m₂ = (12285 + 4095) / 182

    m₂ = 16380/182

    m₂ = 90 g.

    Thus the mass of the other ball = 90 g
  2. 7 October, 11:43
    0
    Answer: M2 = 90g

    Therefore, the mass of the other ball is 90g

    Explanation:

    According to the law of conservation of momentum.

    M1U1 + M2U2 = M1V1 + M2V2 ... 1

    Where,

    M1 and M2 are mass of golf ball and another ball

    U1 and U2 are their initial velocities

    V1 and V2 are their final velocities

    From equation 1

    M1U1 - M1V1 = M2V2 - M2U2

    M1U1 - M1V1 = M2V2 - M2U2

    M2 = (M1U1 - M1V1) / (V2-U2) ... 2

    Given;

    M1 = 45g

    U1 = 273km/h

    V1 = - 91km/h. (It moves to opposite direction)

    U2 = 0

    V2 = 182km/h

    Substituting into eqn 2

    M2 = (45*273 - 45 * - 91) / (182-0)

    M2 = 16380/182

    M2 = 90g

    Therefore, the mass of the other ball is 90g
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