A worker does 25 J of work lifting a bucket, then sets the bucket back down in the same place. What is the total net work done on the bucket? a. - 25 J c. 25 J b. 0 J d. 50 J

Question

Physics

Eliezer

6 August, 13:36

A worker does 25 J of work lifting a bucket, then sets the bucket back down in the same place. What is the total net work done on the bucket? a. - 25 J c. 25 J b. 0 J d. 50 J

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Answers (2)

Know the Answer?

Riya Harrison · Answer 1

b. 0 J

Explanation:

Work is the cross product of force and displacement. Since the bucket has 0 displacement, the net work is 0 J.

Noah Morales · Answer 2

0 J this says that is there is no work done on the bucket

Option: b

Explanation:

Work is the scalar multiplication of force (F) and the displacement (d). In this particular question work done in lifting the bucket is 25 J. The worker lifts the bucket and puts the bucket down in the same place so displacement is zero. If the "displacement" is zero then there is no 'work' has been done by the worker. Since the bucket is kept back to the original position, there is no change in "potential energy". According to the "work-energy theorem," there is no network done. As the "displacement" is zero so the 'network done' is also zero.