While leaning out a window that is 5.70 m above the ground, you drop a 0.600-kg basketball to a friend at ground level. Your friend catches the ball at a height of 2.00 m above the ground. Determine the following.

(a) the amount of work done by the force of gravity on the ball

(b) the gravitational potential energy of the ball-Earth system, relative to the ground when it is released

(c) the gravitational potential energy of the ball-Earth system, relative to the ground when it is caught

(d) the ratio of the change (PEf - PE0) in the gravitational potential energy of the ball-earth system to the work done on the ball by the force of gravity

Question

Physics

Karlee Lyons

1 September, 00:08

While leaning out a window that is 5.70 m above the ground, you drop a 0.600-kg basketball to a friend at ground level. Your friend catches the ball at a height of 2.00 m above the ground. Determine the following.

(a) the amount of work done by the force of gravity on the ball

(b) the gravitational potential energy of the ball-Earth system, relative to the ground when it is released

(c) the gravitational potential energy of the ball-Earth system, relative to the ground when it is caught

(d) the ratio of the change (PEf - PE0) in the gravitational potential energy of the ball-earth system to the work done on the ball by the force of gravity

+1

Answers (1)

Know the Answer?

Konner Bautista · Answer 1

a) 21.756 J

b) 33.516 J

c) 11.52 J

d) - 1

Explanation:

Net fall in height of ball = 5.70-2.0 = 3.70 m

a) work done by the force of gravity on the ball = Mg*h = 0.6*9.8*3.7 = 21.756 J

b) gravitational potential energy of the ball-earth system, relative to the ground when it is released = 0.6*9.8*5.70 = 33.516 J (ans)

c) the gravitational potential energy of the ball-earth system, relative to the ground when it is caught = 0.6*9.8*2 = 11.52 J

d) ratio of the change (PE_f - PE_0) in the gravitational potential energy of the ball-earth system to the work done on the ball by the force of gravity = (11.52 - 33.51) / (21.756) ≅-1 (ans)