The runner reaches the first camera, at the 500 m mark, at 9:03:05 a. m. and the second camera, at the 600 m mark, at 9:03:25 a. m. What is her average speed over that time interval

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Physics

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27 January, 08:13

The runner reaches the first camera, at the 500 m mark, at 9:03:05 a. m. and the second camera, at the 600 m mark, at 9:03:25 a. m. What is her average speed over that time interval

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Ahmed · Answer 1

Distance travelled = 600 - 500 = 100 m

Time taken = 9:03:25 a. m. - 9:03 : 05 a. m.

= 20 s

average speed = distance / time taken

= 100 / 20 m / s

= 5 m / s