A 20.5 kg box initially at rest is pushed 5.93 m along a rough, horizontal floor with a constant applied horizontal force of 95.3501 N. If the coefficient of friction between box and floor is 0.389, find the work done by the applied force.

Question

Physics

Cody Nguyen

27 November, 10:15

A 20.5 kg box initially at rest is pushed 5.93 m along a rough, horizontal floor with a constant applied horizontal force of 95.3501 N. If the coefficient of friction between box and floor is 0.389, find the work done by the applied force.

+4

Answers (1)

Know the Answer?

Karley Riley · Answer 1

W = 565.42 J

Explanation:

Given that

mass, m = 20.5 kg

displacement = 5.93 m

Applied force, F = 95.3501 N

Coefficient of friction,μ = 0.389

We know that work done by force F is given as

W = F. d

d=Displacement

F=Force

W=Work

W = 95.3501 x 5.93 J

W = 565.42 J

Therefore the work done by applied force will be 565.42 J.