A 0.030-m3 container is initially evacuated. Then, 4.0 g of water is placed in the container, and, after some time, all the water evaporates. If the temperature of the water vapor is 388 K, what is its pressure?

Question

Physics

Elena Lewis

7 September, 21:21

A 0.030-m3 container is initially evacuated. Then, 4.0 g of water is placed in the container, and, after some time, all the water evaporates. If the temperature of the water vapor is 388 K, what is its pressure?

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Answers (1)

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Andreas Turner · Answer 1

23895.05 Pa

Explanation:

V = 0.03 m³

mass, m = 4 g

Temperature, T = 388 K

Let P be the pressure.

number of moles, n = 4 / 18 = 0.22

Use ideal gas equation

PV = n RT

P x 0.03 = 0.22 x 8.314 x 388

P = 23895.05 Pa

Thus, the pressure is 23895.05 Pa.