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7 September, 21:21

A 0.030-m3 container is initially evacuated. Then, 4.0 g of water is placed in the container, and, after some time, all the water evaporates. If the temperature of the water vapor is 388 K, what is its pressure?

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  1. 7 September, 21:42
    0
    23895.05 Pa

    Explanation:

    V = 0.03 m³

    mass, m = 4 g

    Temperature, T = 388 K

    Let P be the pressure.

    number of moles, n = 4 / 18 = 0.22

    Use ideal gas equation

    PV = n RT

    P x 0.03 = 0.22 x 8.314 x 388

    P = 23895.05 Pa

    Thus, the pressure is 23895.05 Pa.
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