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1 April, 23:06

What mass, in grams, of aluminum fins could 2571 J of energy heat from 15.73 ∘C to 26.50 ∘C? Aluminum has a specific heat of 0.897 (J/g) ⋅∘C. Express your answer to three significant figures.

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  1. 2 April, 01:01
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    266 g or 0.266 kg

    Explanation:

    The formula for specific heat capacity is given as,

    Q = cm (t₂-t₁) ... Equation 1

    Where Q = Heat Energy, c = specific heat capacity of Aluminum, m = mass of the aluminum fins, t₁ = initial temperature, t₂ = final temperature.

    make m the subject of the equation,

    m = Q/c (t₂-t₁) ... Equation 2

    Given : Q = 2571 J, c = 0.897 J/g.°C, t₁ = 15.73 °C, t₂ = 26.50 °C.

    Substitute into equation 2

    m = 2571/[0.897 * (26.5-15.73) ]

    m = 2571/9.661

    m = 266 g or 0.266 kg

    Hence the mass of the Aluminum fins = 266 g or 0.266 kg
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