Ask Question
5 October, 11:18

You are using a rope to lift a 14.5 kg crate of fruit. Initially you are lifting the crate at 0.500 m/s. You then increase the tension in the rope to 150 N and lift the crate an additional 1.15 m. During this d motion, how much work is done on the crate by the tension force?

+3
Answers (1)
  1. 5 October, 12:55
    0
    W = 172.5 J

    Explanation:

    given,

    mass of the fruit crate = 14.5 kg

    initial velocity to lift = 0.500 m/s

    increase in the tension = 150 N

    lift of crate = 1.15 m

    work done by the tension = ?

    work done = force x displacement

    W = F s cos θ

    θ = 0°

    W = F s x cos 0

    W = 150 x 1.15 x 1

    W = 172.5 J

    Work done on the crate by the tension force = W = 172.5 J
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “You are using a rope to lift a 14.5 kg crate of fruit. Initially you are lifting the crate at 0.500 m/s. You then increase the tension in ...” in 📘 Physics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers