Ask Question
4 September, 07:33

A 8.0 µF capacitor is initially connected to a 2.0 V battery. Once the capacitor is fully charged the battery is removed and a 6.0 Ω resistor is connected between the two terminals of the capacitor. Find the current flowing through the resistor 13.0 µsec after the capacitor begins to be discharged.

+4
Answers (1)
  1. 4 September, 10:24
    0
    I = 0.451 amp

    Explanation:

    given,

    C = 8.0 µF

    V = 2 V

    resistor connected between two terminal = 6 Ω

    current flowing through resistor = 13 µsec

    Q = CV

    Q = 8 x 2

    Q = 16 µC

    for an RC discharge circuit

    V = V_0e^{-/dfrac{t}{RC}}

    I = / dfrac{-Q_0}{RC}e^{-/dfrac{t}{RC}}

    t = 13 µsec

    I = / dfrac{-16}{6/times 2}e^{-/dfrac{13}{6/times 2}}

    I = 0.451 amp

    neglecting - ve sign just to show direction.
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “A 8.0 µF capacitor is initially connected to a 2.0 V battery. Once the capacitor is fully charged the battery is removed and a 6.0 Ω ...” in 📘 Physics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers