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27 May, 21:04

Suppose you wanted to use the Earth's magnetic field to make an AC generator at a location where the magnitude of the field is 0.50 mT. Your coil has 1000.0 turns and a radius of 5.0 cm. At what angular velocity would you have to rotate it in order to generate an emf of amplitude 1.0 V?

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  1. 27 May, 22:23
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    The angular velocity I would have to rotate it in order to generate an emf of amplitude 1.0 V is 254.65 rad/s

    Explanation:

    given information:

    B = 0.5 mT = 0.0005 T

    N = 1000

    r = 5 cm = 0.05 m

    emf, ε = 1 V

    according to Faraday's law

    ε = - N dΦ/dt, Φ = B A

    = - N d (B A) / dt

    = - N d (B A cos ωt) / dt

    = - N B A d (cos ωt) / dt

    = N B A ω sin ωt

    A = πr², so

    ε = N B πr² ω sin ωt

    where

    ε = emf

    N = number of coil turn

    B = magnetic field

    r = radius

    ω = angular velocity

    Φ = magnetic flux

    emf maximum, sin ωt = 1. So,

    ε = N B πr² ω

    ω = ε/N B πr²

    = 1/[ (1000) (0.0005) π (0.05) ²

    = 254.65 rad/s
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