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15 February, 13:24

An electric car accelerates for 9.9 s by drawing energy from its 340-V battery pack. During this time, 1700 C of charge pass through the battery pack. Find the minimum power rating of the car

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Answers (2)
  1. 15 February, 17:08
    0
    Given:

    Time, t = 9.9 s

    Charge, Q = 1700 C

    Potential difference, V = 340 V

    Power = IV

    I * t = Q

    Power = (1700 * 3400) / 9.9

    = 58383.8 W

    = 58.38 kW.
  2. 15 February, 17:10
    0
    78.26hp

    Explanation:

    q = 1700C

    V=340V

    t = 9.9s

    1hp=746W

    Energy obtained from the car = qv/t = 1700*340/9.9 * 1hp/746W = 78.26hp
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