A ball initially at rest rolls down a hill and has an acceleration of 3.3 m/s². If it accelerates for 7.5 s, how far will it move during this time?

F. 12 m

G. 93 m

H. 120 m

J. 190 m

G. 93 m

Explanation:

Applying the equation of motion,

s = ut + 1/2at² ... Equation 1

Where s = distance, u = initial velocity, t = time, a = acceleration.

Given: u = 0 m/s (at rest), a = 3.3 m/s², t = 7.5 s.

Substitute into equation 1

s = 0 (7.5) + 1/2 (3.3) (7.5) ²

s = 0 + 185.625/2

s = 185.625/2

s = 92.8

s ≈ 93 m

Hence the right option is G. 93 m