A room is 16 ft x 12 ft x 12 ft. would air enter or leave the room if the temperature changed from 27°c to - 3°c while the pressure remained constant? Determine the volume of the air which moved in or out of the room.

v = 6.52 m³

convert meter to foot we get

v=230.2 ft³

Explanation:

Given Data

Room dimension=16ft*12ft*12ft

Temperature changed from 27°c to - 3°c

To find

Volume of air

Solution

V (Volume of the room) = 16ft x 12ft x 12ft

V = 2304 ft³

convert foot to meter we get

V = 65.242 m³

R=8.205 * 10⁻⁵ m³ atm / K mol ... Gas Constant

Pressure = 1 atm ... as it remained constant

Initially moles of gas = PV / RT

n = 65.242 / 8.205 * 10⁻⁵ x (273 + 27)

n = 2650.50

As the temperature changes the new volume for these moles = nRT / P

m = 2650.5 x 8.205 * 10⁻⁵ x (273 - 3) / 1

m = 58.72 m³

So the difference = 65.24 m³ - 58.72 m³

v = 6.52 m³

convert meter to foot we get

v=230.2 ft³