Ask Question
20 February, 20:34

A cue stick hits a cue ball with an average force of 22 N for a duration of 0.029 s. If the mass of the ball is 0.15 kg, how fast is it moving after being struck?

+5
Answers (2)
  1. 20 February, 22:36
    0
    4.25 m/s

    Explanation:

    Force, F = 22 N

    Time, t = 0.029 s

    mass, m = 0.15 kg

    initial velocity of the cue ball, u = 0

    Let v be the final velocity of the cue ball.

    Use newton's second law

    Force = rate of change on momentum

    F = m (v - u) / t

    22 = 0.15 (v - 0) / 0.029

    v = 4.25 m/s

    Thus, the velocity of cue ball after being struck is 4.25 m/s.
  2. 20 February, 23:35
    0
    4.25 m/s

    Explanation:

    An impulse is defined as a change in momentum, and can be found my multiplying an applied force by its duration. In this case,

    that's 22*0.029 = 0.638 kg-m/s. Momentum is also mass times velocity, and your velocity is unknown.

    Momentum P = mv

    0.15 v = 0.638

    v = 4.25 m/s
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “A cue stick hits a cue ball with an average force of 22 N for a duration of 0.029 s. If the mass of the ball is 0.15 kg, how fast is it ...” in 📘 Physics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers