3. A 3.0 * 10-3 kg copper penny drops a distance of 50.0 m to the ground. If 65 percent of the initial potential energy goes into increasing the internal energy of the penny, determine the magnitude of that increase.

The magnitude of the increase is 0.9555J

Explanation:

Potential Energy (PE) = mgh

mass (m) = 3*10^-3kg, acceleration due to gravity (g) = 9.8m/s^2, distance (h) = 50m

PE = 3*10^-3 * 9.8 * 50 = 1.47J

Increase in internal energy = 65% of 1.47J = 0.65 * 1.47J = 0.9555J