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17 November, 20:49

A golfer angles a shot at 18.0° to the horizontal with an initial velocity of 62.0 m/s. How far does the ball travel before striking the ground? Ignore air resistance.

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  1. 17 November, 21:23
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    372.67m

    Explanation:

    R=Ux cos 18 * t

    = 62 cos 18 x (63:9.81)

    =372.67m

    because t = u/g

    g = 9.81
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