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3 January, 07:04

A 6kg rock is thrown vertically upward from the top of a cliff that is 28m high. It was thrown with a speed of 11ms. Calculate the greatest height of the rock as measured from the base of the cliff.

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  1. 3 January, 08:03
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    Answer:H=34.05m

    Explanation: H=u²/2g + 28m height of the cliff

    u=11ms⁻¹

    g=10ms⁻²

    H=11²/2*10

    H=121/20

    H=6.05+28

    H=34.05m
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