if a spring stores 5j of energy when it is compressed by0.5m, what is the spring constant of the spring?

K = 40N/m

Explanation:

According to Hooke's law

Energy = 1/2 kx^2

K is the spring constant

x = displacement

From the question

Energy = 5J

x = 0.5m

K = ?

Using the above formula,

We have

5 = 1/2 x k x (0.5) ^2

5 = 1/2 x k x (0.5 x 0.5)

5 = 1/2 x k x 0.25

5 = 0.25k / 2

Cross multiply

5 x 2 = 0.25k

10 = 0.25k

Divide both sides by 0.25 to get k

10/0.25 = 0.25k / 0.25

40 = k

K = 40N/m