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30 August, 18:22

A puck of mass m = 0.085 kg is moving in a circle on a horizontal frictionless surface. It is held in its path by a massless string of length L = 0.72 m. The puck makes one revolution every t = 0.45 s. Part (a) What the magnitude of the tension in the string, in newtons, while the puck revolves?

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  1. 30 August, 18:56
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    T = 11.93 N

    Explanation:

    Newton's second law to the puck in the circular path

    ∑F = m*a Formula (1)

    ∑F : algebraic sum of the forces in radial direccion (N)

    m : puck mass (kg)

    a : radial acceleration of the puck (m/s²)

    dа ta:

    m = 0.085 kg

    L = 0.72 m = R : radium of the circular path (m)

    θ = one revolution = 2Π rad

    t = 0.45 s

    Angular speed of the puck

    ω = θ/t

    ω = 1 rev/0.45 s = (2π/0.45) rad/s

    ω = 13.96 rad / s

    Radial acceleration or centripetal

    a = ω²*R

    a = (13.96) ² * (0.72)

    a = 140.3 m/s²

    Magnitude of the tension in the string (T)

    We apply the Formula (1)

    ∑F = m*a

    T = (0.085 kg) * (140.3 m/s²)

    T = 11.93 N
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