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19 August, 15:49

Two charged particles are accelerated through a uniform electric field and zero magnetic field, then enter a region with zero electric field and a uniform magnetic field. The particles start at rest from the same position (but at different times; they do not interact with each other). They have identical charges, but different masses. Particle 2 has a cyclotron radius 1.5 times as large as that of particle 1. Find ratio m2/m1

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  1. 19 August, 18:20
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    In magnetic field, charged particle will have circular path. Let the radius of their circular path be r₁ and r₂. Let their velocity at the time of entering magnetic field be v₁ and v₂.

    The velocity with which they will come out of electric field can be measured from following equation

    Eq = 1/2 m v², E is electric field, q is charge on the particle, m is mass and v is velocity.

    v² = 2Eq / m

    radius of circular path can be measured by the following expression

    m v² / r = Bqv

    2Eq / r = Bqv

    r = 2Eq / Bqv

    = 2E / Bv

    r² = 4E² / B²v²

    = 4E²m / B²x 2Eq

    since E, B and q are constant

    r² = K. m

    r₂² / r₁² = m₂ / m₁

    1.5²

    m₂ / m₁ = 1.5²

    = 2.25
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