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11 August, 07:12

The friends now feel prepared for a homework problem. Consider a cylinder initially filled with 9.30 10-4 m3 of ideal gas at atmospheric pressure. An external force is applied to slowly compress the gas at constant temperature to 1/6 of its initial volume. Calculate the work that is done. Note that atmospheric pressure is 1.013 105 Pa

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  1. 11 August, 10:06
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    Initial volume of gas V₁ = 9.30 x 10⁻⁴ m³

    final volume V₂ = 1 / 6 x 9.30 x 10⁻⁴

    = 1.55 x 10⁻⁴ m³

    Atmospheric pressure P = 1.013 x 10⁵ Pa.

    temperature T.

    PV = n RT

    nRT = 1.013 x 10⁵ x 9.3 x 10⁻⁴

    = 94.21

    work done in isothermal process

    = 2.303 nRT log V₁ / V₂

    = 2.303 x 94.21 log 6

    = 168.83 J.
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