A constant force of 53 newtons was applied to a 12-kilogram mass for 15 seconds. a.) What was the change in momentum of the mass?

b.) What was the change in velocity of the object?

Question

Physics

Tania Phelps

9 May, 23:56

A constant force of 53 newtons was applied to a 12-kilogram mass for 15 seconds. a.) What was the change in momentum of the mass?

b.) What was the change in velocity of the object?

+1

Answers (1)

Know the Answer?

Beau Barry · Answer 1

Impulse = change in momentum

FΔt = Δp

(53 N) (15 s) = Δp

Δp = 795 kg m/s

For constant mass:

Δp = m Δv

795 kg m/s = (12 kg) Δv

Δv = 66.25 m/s

Rounding to two significant figures, Δp = 800 kg m/s and Δv = 66 m/s.

A constant force of 53 newtons was applied to a 12-kilogram mass for 15 seconds. a.) What was the change in momentum of the mass?b.) What was the change in velocity of the object?

A constant force of 53 newtons was applied to a 12-kilogram mass for 15 seconds. a.) What was the change in momentum of the mass?

b.) What was the change in velocity of the object?