Determine the energy stored in a parallel plate capacitor that is charged to a potential difference of 150 V. The plates are 4.50 mm apart and have an area of 87.5 cm2. Assume the space between the plates is filled with air.

Answer: E = 1.93*10^-7 J

Explanation: The formulae for getting the energy stored in a capacitor is given as

E = Cv²/2

Where E = energy stored in capacitor (joules), C = capacitance of capacitor (farad), v = applied voltage = 150v.

The formulae implies that we need to get the capacitance of the capacitor (C) first before we can get the energy.

From the parameters given to us

Area of plates = A = 87.5cm² = 87.5/10000 = 0.00875m²

Distance between plates = d = 4.50mm = 4.50/1000 = 0.0045m

C = ε0A/d

Where ε0 = permittivity of free space = 8.85*10^-12 F/m

C = 8.85*10^-12 * 0.00875 / 0.0045

C = 7.743*10^-14/0.0045

C = 1.72*10^-11 F.

Recall that E = Cv²/2

E = (1.72*10^-11 * 150*150) / 2

E = 3.87*10^-7/2

E = 1.93*10^-7 J