A sprinter accelerates from rest to a velocity of 12m/s in the first 6 seconds of the 100 meter dash.

a) how far does the sprinter travel during the first 6 seconds?

b) how much farther does the sprinter have to travel to reach the finish line?

Question

Physics

Phillip Vega

1 December, 22:21

A sprinter accelerates from rest to a velocity of 12m/s in the first 6 seconds of the 100 meter dash.

a) how far does the sprinter travel during the first 6 seconds?

b) how much farther does the sprinter have to travel to reach the finish line?

+1

Answers (1)

Know the Answer?

Gianna Poole · Answer 1

a) 36 m

b) 64 m

Explanation:

Given:

v₀ = 0 m/2

v = 12 m/s

t = 6 s

Find: Δx

Δx = ½ (v + v₀) t

Δx = ½ (12 m/s + 0 m/s) (6 s)

Δx = 36 m

The track is 100 m, so the sprinter still has to run another 64 m.

A sprinter accelerates from rest to a velocity of 12m/s in the first 6 seconds of the 100 meter dash.a) how far does the sprinter travel during the first 6 seconds?b) how much farther does the sprinter have to travel to reach the finish line?

A sprinter accelerates from rest to a velocity of 12m/s in the first 6 seconds of the 100 meter dash.

a) how far does the sprinter travel during the first 6 seconds?

b) how much farther does the sprinter have to travel to reach the finish line?