A Thomson's gazelle can run at very high speeds, but its acceleration is relatively modest. A reasonable model for the sprint of a gazelle assumes an acceleration of 4.2 m/s2m/s2 for 6.5 ss, after which the gazelle continues at a steady speed. What is the gazelles top speed?

v = 27.3 m/s

Explanation:

Given that

Acceleration, a = 4.2 m/s²

Time, t = 6.5 s

Lets take the maximum speed gain by Thomson's = v

We know that, if acceleration is constant then the speed v is given as

v = u + a t

v=final speed

u=initial speed

a=acceleration

t=time

Here the initial speed of Thomson's, u = 0 m/s

Now by putting the values in the above equation we get

v = 0 + 4.2 x 6.5 m/s

v = 27.3 m/s

Therefore the maximum speed gain by Thomson will be 27.3 m/s.