before colliding, the momentum of block A is + 15.0 kg m/s. after, block A has a momentum - 12.0 kg*m/s. what is the momentum of block B afterwards

The momentum of block B = 27 Kg m/s

Explanation:

Given,

The initial momentum of block A, MU = 15 Kg m/s

The final momentum of block A, MV = - 12 Kg m/s

Consider the block B is initially at rest.

Therefore, the initial momentum of block B, mu = 0

According to the laws of conservation of linear momentum, the momentum of the body before impact is equal to the momentum of the body after impact.

MU + mu = MV + mv

15 + (0) = (-12) + mv

mv = 15 + 12

= 27 Kg m/s

Hence, the momentum of the block B after impact is, mv = 27 Kg m/s