A 13-N east horizontal force acts in the same direction as a 6.4kg block as it slides 2.5m/s on a frictionless, horizontal surface for 2.1s. What is the speed of the block after force is applied?

6.77 m/s

Explanation:

Acceleration = Force/mass;

The block is accelerated by 13/6.4 m/s^2 for 2.1s from an initial velocity of 2.5m/s.

Applying the equation of motion:

Vf=Vi + at

Where Vf is the final velocity, Vi is the initial velocity, a is the acceleration and t is the time for which the object accelerates.

Vf = 2.5 + ((13/6.4) * 2.1);