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3 November, 16:00

A small but bright light is at the bottom of a pool 2.2 m deep. How wide is the circle of light that exits the surface of the water when that light shines in the middle of the night? Remember that nwater=1.33 .

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  1. 3 November, 17:03
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    Answer: 1.65m

    Explanation:

    Refractive index in terms of the depth of liquid is the ratio of the real depth to the apparent depth of the liquid i. e Refractive index = Real depth/apparent depth

    Refractive index of water given = 1.33

    Real depth is the measure of how deep is the liquid while apparent depth is the depth at the surface of the liquid.

    Real depth = 2.2m

    Apparent depth = ?

    Applying the formula above

    Apparent depth = Real depth/refractive index

    = 2.2/1.33

    = 1.65m

    Therefore, the circle of light that exits the surface of the water when that light shines in the middle of the night is 1.65m wide
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