A ball is thrown straight up from a bridge at a speed of 11.0 m/s. What will be its velocity (speed and direction) after 2.0 seconds?

Speed of ball after 2 seconds is 8.62 m/s downward.

Explanation:

Let upper direction be positive

We have equation of motion v = u + at

Initial velocity, u = 11 m/s

Final velocity, v = ?

Time, t = 2 s

Acceleration, a = - 9.81 m/s²

Substituting

v = u + at

v = 11 + - 9.81 x 2

v = - 8.62 m/s

Speed of ball after 2 seconds is 8.62 m/s downward.