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10 October, 00:11

How deep would you have to go

in a mine shaft to reach a pressure

of 2.00 atm? (Assume the density

of air remains a constant

1.29 kg/m^3.)

(Unit = m)

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Answers (1)
  1. 10 October, 03:09
    0
    8010 m

    Explanation:

    P = Patm + ρgh

    2.00 atm = 1.00 atm + (1.29 kg/m³) (9.8 m/s²) h (9.87*10⁻⁶ atm/Pa)

    h ≈ 8010 m
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