Ask Question
28 September, 20:30

A 35.0 kg child slides down a long slide in a playground. She starts from rest at a height h1 of 24.00 m. When she is partway down the slide, at a height h2 of 12.00 m, she is moving at a speed of 6.70 m/s. Calculate the mechanical energy lost due to friction (as heat, etc.).

+3
Answers (1)
  1. 28 September, 23:08
    0
    The mechanical energy loss is 3330.425 Joules.

    Explanation:

    The mechanical energy lost due to the work of non-conservative forces is given by:

    Wncf = ΔEm = Emf - Emi

    Where Emf is the final mechanical energy and Emi is the initial mechanical energy.

    The mechanical energy i:

    Em = Ek + Ep

    where:

    -The kinetic energy:

    Ek = 0.5mv² (m is the mass and v is the speed)

    -The gravitational potential energy:

    Ep = mgh (m is the mass, g the acceleration of gravity and h is the height)

    Therefore:

    Emi = Eki + Epi

    The initial kinetic energy is zero because she starts from rest.

    Emi = Epi = mgh1

    Emi = (35.0) (9.8) (24.00)

    Emi = 8232 Joules.

    Emf = Ekf + Epf = 0.5mv² + mgh2

    Emf = 0.5 (35.0) (6.70) ² + (35.0) (9.8) (12.00)

    Emf = 4901.575 Joules.

    The variation of mechanical energy is:

    Emf - Emi = 4901.575 - 8232 = - 3330.425 J

    Therefore the loss is 33340.425 J
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “A 35.0 kg child slides down a long slide in a playground. She starts from rest at a height h1 of 24.00 m. When she is partway down the ...” in 📘 Physics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers