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3 November, 00:10

A charged particle is accelerated in a uniform electric field. When its velocity is 2 m/s, its electric potential energy is 100 J and its kinetic energy is 10 J. What is the particle's potential energy when its velocity reaches 4 m/s?

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  1. 3 November, 01:28
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    particle's potential energy = 70J

    Explanation:

    From conservation of energy; K1 + Ue1 = K2 + Ue2

    where K1 and K2 are the kinetic energies at two positions and Ue1 and Uue2 are the electrical potential energies at two positions.

    k1 = 10J, Ue1 = 100J

    K2 = 40J

    substitute into K1 + Ue1 = K2 + Ue2

    Ue2 = K1 + Ue1 - K2

    = 10 + 100 - 40

    Ue2 = 70J
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