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14 January, 02:02

Suppose the Solar radiation is 850 W/m2 and you collect 20% of energy that falls on the reflecting surface of a hot dog cooker. If you need 240 watts for the cooker, what is the minimum collector area?

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  1. 14 January, 05:11
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    The minimum collector area is 1.412 m2 (rounded to 3 decimal places)

    Explanation:

    Stepwise procedure-

    Total solar radiation falling / unit area = 850 W/m2

    Given = Only 20% of the energy is collected

    Need = 240 W

    The Minimum surface area of collector=?

    Let the minimum surface area be "x" m2

    Total solar radiation falling = radiation / unit area * total area

    = x*850 W/m2

    Total solar radiation utilised = (20/100) * x*850 (given only 20% is utilised)

    Since the need is 240 W

    Hence the total solar radiation utilised = energy needed

    Thus 240 = (x*850) / 5

    x = (240*5) / 850

    The minimum collector area is "x" = 1.412 m2
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