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19 June, 02:53

In a certain region of space, the electric field is constant in direction (say horizontal, in the x direction), but its magnitude decreases from E = 560 N/C at x = 0 to E = 410 N/C at x = 25 m. Determine the charge within a cubical box of side l = 25 m, where the box is oriented so that four of its sides are parallel to the field lines.

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  1. 19 June, 03:40
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    8.3 x 10⁻⁷ C

    Explanation:

    Electric flux will enter the face at x=0 and exit at face x = 25 m

    On the other faces, field lines are parallel so no flux will enter or exit.

    Flux entering the face at x = 0

    = electric field x face area

    = 560 x 25 x 25 = 350000 weber

    Flux exiting the face at x = 25

    = 410 x 25 x25

    = 256250 weber

    Net flux exiting from cube (closed face)

    350000 - 256250 = 93750 web

    Apply gauss'es theorem

    Q / ε = Flux coming out

    Q is charge inside the closed cube

    Q / ε = 93750

    Q = 8.85 x 10⁻¹² x 93750

    = 8.3 x 10⁻⁷ C
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