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12 December, 08:51

an object of mass 0.5kg at rest, started to fall aheigh of 180cm from the surface of earth. it's momentum when it reaches the earth's surface is

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  1. 12 December, 09:21
    0
    m=0.5kg

    h = 180 cm = 1.8 mh=180cm=1.8m

    Initial potential energy of the object is:

    E_p=m*g*hE

    p

    = m∗g∗h

    Kinetic energy at the surface:

    E_k=/frac{mv^2}{2}E

    k

    =

    2

    mv

    2

    According to the law of conservation of energy (assuming no air resistance):

    E_p = E_kE

    p

    = E

    k

    mgh=/frac{mv^2}{2}mgh=

    2

    mv

    2

    Solving for v:

    v=/sqrt{2gh}v=

    2gh



    p=mvp=mv

    So,

    p = m*v = m/sqrt{2gh}p=m∗v=m

    2gh



    Calculating:

    p = 0.5/sqrt{2*9.8*1.8}/approx 2.97 / frac{kg*m}{s}p=0.5

    2∗9.8∗1.8

    ≈2.97

    s

    kg∗m

    Answer:

    p / approx 2.97 / frac{kg*m}{s}p≈2.97

    s

    kg∗m
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