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25 July, 05:24

During a hard stop, a car and its passengers slow down with an acceleration of 8,0m/s^2. What magnitude force does a 50-kg passenger exert on the seat belt in such a stop?

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  1. 25 July, 07:29
    0
    F = 400 N

    Explanation:

    Given,

    The acceleration of the car, a = 8 m/s²

    The mass of the passenger, m = 50 Kg

    The force acting on a body is equal to the product of the mass and its acceleration

    F = m x a newtons

    Substituting the given values in the above equation,

    F = 50 Kg x 8 m/s²

    = 400 N

    Hence, the force exerted by the person on the seat belt is, F = 400 N
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