A 7.12 uC charge is moving at one half the speed of light perpendicular to a magnetic field of 4.02 mT. How large is

the force on the charge?

4.29N

32.90 x 10^1 N

4.29 x 10^12 N

1.00 x 10^16 N

Correct answer: F = 4.29 N

Explanation:

A charged particle moving in a magnetic field is affected by a magnetic force called the Lorentz force and is calculated by the formula.

F = q · v · B sinα

where q is the particle charge, v is the velocity of the particle, B is the magnetic field strength and the alpha - α is the angle between the velocity vector and the direction of the magnetic field vector.

In this case angle α = 90° = > sinα = 1

F = 7.12 · 10⁻⁶ C · 1.5 10⁸ m/s · 4.02 10⁻³ T = 42.93 · 10⁻¹ = 4.29 N

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