A 100-kg box is sitting on a 10 degree incline with a coefficient of friction of 0.5. At what angle must the incline be raised to start sliding on the box?

26.56°

Explanation:

μ = 0.5

F = ?

N = ?

Fs = μN

Fs = force acting due to friction (on an inclined plane)

N = normal force.

μ = coefficient of friction

μ = tanΘ

μ = tan 0.5

Θ = tan⁻¹ 0.5

Θ = 26.56°

The angle in which is required for the box to start moving across the inclined plane is 26.56°