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14 November, 09:52

3. A clown rides a small car at a speed of

15 km/h along a circular path with a

radius of 3.5 m. What is the

magnitude of the centripetal force on a

0.18-kg ball held by the clown?

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Answers (1)
  1. 14 November, 11:45
    0
    0.89 N

    Explanation:

    Centripetal force is mass time centripetal acceleration.

    F = ma

    F = m v² / r

    Given m = 0.18 kg, v = 15 km/h = 4.17 m/s, and r = 3.5 m:

    F = (0.18 kg) (4.17 m/s) ² / (3.5 m)

    F = 0.89 N
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