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29 September, 12:02

wooden floor at a constant speed of 1.0 m/s. The coefficient of kinetic friction is 0.15. Now you double the force on the box. How long would it take for the velocity of the crate to double to 2.0 m/s?

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  1. 29 September, 14:49
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    Time = 1.36s

    Explanation:

    coefficient of kinetic friction = μk

    μk = F/N = F / mg

    where m = mass of the body

    g = acceleration due to gravity.

    Doubling the force on the box we have,

    μk = 2ma/mg

    hence μk = 0.15/2 = 0.075

    To determine the time it takes to reach a velocity of 2m/s from 1m/s.

    From Newton law of motion,

    v = u + a*t

    for a deceleration of a = μk x g

    2m/s = 1m/s + 0.075 x 9.8m/s² x t

    t = (2m/s - 1m/s) / 0.735m/s²

    t = 1.36 seconds ...

    it will take the 1.36s for the crate to double to 2.0m/s
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